Oracle 1z0-082 Korean valid dump torrent : Oracle Database Administration I (1z0-082 Korean Version)
- Exam Code: 1z0-082-KR
- Exam Name: Oracle Database Administration I (1z0-082 Korean Version)
- Updated: Oct 23, 2026
- Q&As: 165 Questions and Answers
About Oracle 1z0-082 Korean Valid Dump
Oracle 1Z1-082 certification exam is designed for professionals who are interested in pursuing a career as an Oracle database administrator. 1z0-082-KR exam is the first step towards earning the Oracle Certified Associate (OCA) certification in Oracle Database Administration. 1z0-082-KR exam evaluates your knowledge of various database administration tasks, such as installation and configuration, backup and recovery, and performance tuning.
Reference: https://education.oracle.com/oracle-database-administration-i/pexam_1Z0-082
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Oracle 1Z1-082 exam is a computer-based test that consists of 82 questions. 1z0-082-KR exam is divided into two parts: the first part consists of multiple-choice questions, while the second part consists of performance-based questions. 1z0-082-KR exam is designed to test the candidate's knowledge of Oracle Database Administration concepts and skills in installing, configuring, and managing Oracle databases.
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Oracle 1z0-082 Korean Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Understanding Oracle Database Architecture - Oracle Database Instance | - Understand Oracle Database instance management - Explain the memory structures (SGA, PGA) - Describe the background processes |
| Managing Schema Objects | - Create and modify tables - Manage constraints (NOT NULL, UNIQUE, PRIMARY KEY, FOREIGN KEY, CHECK) - Create indexes and views - Manage sequences and synonyms |
| Displaying Data from Multiple Tables Using Joins | - Use CROSS joins - Use Equijoins and Non-equijoins - Use OUTER joins (LEFT, RIGHT, FULL) - Join a table to itself using self-join - Describe different types of joins and their features |
| Using Conversion Functions and Conditional Expressions | - Apply the NVL, NULLIF, and COALESCE functions - Use nested functions - Use the CAST function for data type conversion - Use the TO_CHAR, TO_NUMBER, and TO_DATE conversion functions |
| Retrieving Data using the SQL SELECT Statement | - List the capabilities of SQL SELECT statements - Execute a basic SELECT statement - Use scalar and correlated subqueries - Use SQL row functions (character, number, date, conversion, general) - Describe how schema objects work - Use the ORDER BY clause |
| Reporting Aggregated Data Using the Group Functions | - Use the GROUP BY clause to group data - Use the HAVING clause to filter grouped data - Describe group functions (AVG, SUM, MIN, MAX, COUNT) |
| Restricting and Sorting Data | - Use the NULL operators (IS NULL, IS NOT NULL) - Use the LIKE and IN operators - Use the WHERE clause to limit retrieved rows - Use comparison operators and logical operators (AND, OR, NOT) - Use the BETWEEN comparator - Sort data using the ORDER BY clause |
| Working with Oracle Cloud Exadata Express Cloud Service | - Describe the features and benefits of Exadata Express Cloud Service - Navigate the Exadata Express Cloud Service console - Identify the prerequisites for Exadata Express Cloud Service - Provision and manage an Exadata Express Cloud Service instance |
| Using Single-Row Functions to Customize Output | - Describe the use of conversion functions (TO_CHAR, TO_NUMBER, TO_DATE) - Use CASE and DECODE for conditional expressions - Use character, number, and date functions in SELECT statements - Describe various types of functions available in SQL |
| Using Subqueries to Solve Queries | - Use single-row subqueries with single-row and multiple-row operators - Use scalar subqueries in SQL - Describe the types of subqueries (single-row, multi-row, multiple-column) - Use subqueries in the WHERE clause and HAVING clause - Use multiple-row subqueries with multiple-row operators (IN, ANY, ALL) - Define subqueries |
| Managing Users, Roles, and Privileges | - Create and manage roles - Grant and revoke privileges - Differentiate system privileges and object privileges - Create and manage database user accounts |
| Managing Data in Different Time Zones | - Describe the use of datetime functions (CURRENT_DATE, EXTRACT, LOCALTIMESTAMP) - Use various datetime data types (DATE, TIMESTAMP, INTERVAL) - Explain the concepts of time zones and daylight savings |
| Introduction to Oracle Database | - Explain database storage structures (data blocks, segments, tablespaces, data files) - Describe Oracle processes (PMON, SMON, DBWn, LGWR, CKPT, others) - Describe Oracle Database architecture - Describe Oracle Database instance and memory structures - Explain Oracle Database server architecture - Describe Oracle Database Cloud Service (DBCS) architecture and features |
| Managing Oracle Database Instances | - Use the Automatic Diagnostic Repository (ADR) - View the alert log and access dynamic performance views - Start up and shut down an Oracle Database instance - Manage initialization parameter files (SPFILE, PFILE) |
| Understanding Oracle Database Architecture - Database Storage Structures | - Manage space in tablespaces - Describe tablespaces and data files - Create and manage tablespaces - Describe the logical and physical database structures |
| Using the Set Operators | - Use set operators to combine multiple queries into a single query - Describe set operators (UNION, UNION ALL, INTERSECT, MINUS) |
Oracle Database Administration I (1z0-082 Korean Version) Sample Questions:
DESCRIBE 명령에 대해 참인 세 가지 설명은 무엇입니까? (3개를 선택하세요.)
- A. 각 열에 대해 정의된 모든 제약 조건을 표시합니다.
- B. 해당 제약 조건이 있는 모든 열에 대해 NOT NULL 제약 조건을 표시합니다.
- C. PRIMARY KEY 제약 조건이 있는 열에 대한 PRIMARY KEY 제약 조건을 표시합니다.
- D. 기존 보기의 구조를 표시하는 데 사용할 수 있습니다.
- E. SQL*Plus에서만 사용 가능
- F. SQL Developer에서 사용 가능
Correct Answer: B,D,E 🗳️
Exhibit를 보고 PRODUCTS 테이블의 구조를 검사하십시오.
하위 쿼리가 필요한 두 작업은 무엇입니까? (두 가지를 선택하세요.)
- A. 공급자(102)가 공급한 제품 상태가 단종된 총 제품 수 표시
- B. PROD_MIN_PRICE가 모든 제품의 평균 PROD_LIST_PRICE보다 높고 상태가 주문 가능한 제품 표시
- C. PROD_LIST_PRICE가 1000 미만인 공급업체 표시
- D. 각 제품 상태에 대한 최소 PROD_LIST_PRICE 표시
- E. PROD_LIST_PRICE가 평균 PROD_LIST_PRICE보다 높은 제품 수 표시
Correct Answer: B,E 🗳️
sales 테이블에는 숫자 형식의 prod_id와 quantity_sold 열이 있습니다. 두 쿼리가 모두 성공적으로 실행되었습니까?
- A. SELECT prod_id FROM sales WHERE quantity_sold > 55000 GROUP BY prod_id HAVING COUNT(-) > 10;
- B. SELECT COUNTlprod_id> FROM sales GROUP BY prod_id WHERE quantity_Sold > 55000;
- C. SELECT prod_id FROM sales WHERE quantity_sold > 5S000 AND COUNT(-) > 10 GROUP BY prod_id HAVING COUNT(-) > 10;
- D. SELECT COUNT|prod_id> FROM sales WHERE quantity_sold > 55000 GROUP BY prod_id;
- E. SELECT prod_id FROM sales WHERE quantity_scld > 55000 AND COUNT(-) > 10 GROUP BY COUNT(-) > 10;
Correct Answer: A,D 🗳️
완전 회복에 대한 설명 중 맞는 것은 두 가지입니다. (두 가지를 선택하세요.)
- A. 증분 백업을 사용하면 백업을 수행하는 동안 데이터베이스를 롤포워드할 수 있습니다.
- B. 이 작업을 수행하려면 데이터베이스에 FLASHBACK 기능이 활성화되어 있어야 합니다.
- C. 데이터베이스를 복원할 때 RMAN 백업 세트만 사용할 수 있습니다.
- D. 데이터베이스가 MOUNT 상태일 때만 가능합니다.
- E. 커밋되지 않은 트랜잭션은 완료 후 롤백됩니다.
Correct Answer: B,D 🗳️
다음 쿼리를 실행합니다.
SELECT TO_CHAR(NEXT_DAY(LAST_DAY(SYSDATE), `MON'), `dd "월요일"
fm월 rrrr')
결과는 무엇인가요?
- A. 오류가 발생합니다
- B. 실행은 성공적으로 되지만 결과가 반환되지 않습니다.
- C. 현재 월의 마지막 월요일 날짜를 반환합니다.
- D. 다음 달 첫 번째 월요일 날짜를 반환합니다.
Correct Answer: D 🗳️
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