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IBM Developing with IBM Enterprise PL/I Sample Questions:

1. Which of the following is NOT a characteristic of the RANDOM builtin function?

A) The values generated by RANDOM are uniformly distributed between 0 and 1, where 0 < random() < 1.
B) RANDOM can be called without any parameters.
C) RANDOM can be called with an optional SEED to avoid getting repeatable results.
D) RANDOM can be called with an optional upper bound.

2. In which of the following groups of compiler options could all the options specified cause the compiler to
generate code which requires more time at execution?

A) ATTRIBUTES(FULL),XREF(FULL),DEFAULT(EVENDEC,DUMMY(UNALIGNED)),OFFSET
B) APCH(5),BIFPREC(31),NOTESTMTUNE(5),NOSERVICE
C) OPTIMIZE(0),NOREDUCE,PIREFIX(SIZE,SUBSCRIPTRANGE)
D) OPTIMIZE(2),DEFAULT(REORDER,NOLAXDCL,NOLAXCTL),STORAGE,MMTEMP(1000)

3. Given the following code:
DCL INDATA FILE RECORD INPUT;
DCL INSTRUC CHAR(100);
DCL EOF BIT(1) INIT('0'B);
ON ENDFILE(INDATA) EOF = '1'B;
OPEN FILE(INDATA);
READ FILE(INDATA) INTO(INSTRUC);
DO WHILE (^EOF);
CALL SR_PROCESS;
READ FILE(INDATA) INTO(INSTRUC);
END;
CLOSE FILE(INDATA);
If the database (input file) changes from OS-PS to DB2 view and the necessary syntax has been changed
accordingly, which of the following DB2-related steps is NOT additionally required to guarantee the same
level of stability and functionality?

A) Check the SQLCODE after each EXEC SQL OPEN / CLOSE statement.
B) Check the SQLCODE after each EXEC SQL FETCH statement.
C) Set the EOF bit to '1'B, if SQLCODE = 100 (not found).
D) Check the CURRENT SQLI

4. What does it mean that an interface is synchronous?

A) Requesting program always receives immediate response
B) Requests are processed in parallel
C) Requesting program must wait for a reply
D) Requests are processed randomly

5. PL/I programs which have been written under Intel architecture are now to be recompiled and run on the
mainframe. What will happen to the programs during compilation and execution?

A) They will not compile correctly on mainframe because ASCII has no NOT sign.
B) They will not run correctly because the byte order on mainframe is bigendian.
C) They can be recompiled unchanged and will run correctly.
D) They may have to be changed before they run correctly on the mainframe.

Solutions: